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What is the difference between String and &str in Rust?

Learn the difference between String and &str in Rust — owned heap text versus borrowed slices, deref coercion, and why APIs take &str. With examples.

easyQ7 of 61 in Rust Est. time: 6 minsLast updated:
Open Code Lab

Expected Interview Answer

String is a growable, heap-allocated, owned UTF-8 string that you can mutate, while &str is an immutable borrowed view (a slice) into UTF-8 text that someone else owns.

A String owns its buffer and is responsible for freeing it, so it carries a pointer, length, and capacity and can grow or shrink. A &str is a fat pointer (pointer plus length) that borrows existing bytes — it might point into a String, into a string literal baked into the binary with a 'static lifetime, or into any other UTF-8 buffer. Because a &String coerces to &str automatically via deref, idiomatic APIs accept &str parameters so they work with both owned and borrowed data.

  • String gives ownership and mutability when you need to build or modify text
  • &str is cheap to pass — no allocation or copying, just a borrow
  • Accepting &str makes functions accept both literals and owned Strings
  • Slicing lets you reference part of a string without copying it
  • Both guarantee valid UTF-8 at the type level

AI Mentor Explanation

A String is like owning the actual physical scorebook for a match — you can write new deliveries into it, erase, and add pages because it is yours. A &str is like a photographer pointing a lens at one page: they can read the runs and wickets shown but cannot alter anything, and their view is valid only while the real scorebook stays open in your hands.

Step-by-Step Explanation

  1. Step 1

    Recognize ownership

    String owns a heap buffer with pointer, length, and capacity; &str only borrows bytes it does not own.

  2. Step 2

    Create a String

    Use String::from("hi"), "hi".to_string(), or String::new() then push characters to build growable text.

  3. Step 3

    Borrow as &str

    Pass &my_string; deref coercion turns &String into &str so the function borrows without copying.

  4. Step 4

    Prefer &str in signatures

    Accept &str parameters so callers can pass literals, slices, or owned Strings interchangeably.

  5. Step 5

    Convert when needed

    Call .to_owned() or .to_string() on a &str to get an owned String you can mutate and store.

What Interviewer Expects

  • Clear distinction between owned and borrowed data
  • Understanding that &str is a slice (fat pointer with length)
  • Knowledge of deref coercion from &String to &str
  • Awareness that string literals are &'static str
  • Why idiomatic APIs take &str instead of &String

Common Mistakes

  • Claiming &str is always a substring of a String only
  • Taking &String parameters instead of &str
  • Forgetting that a String owns and frees its heap buffer
  • Thinking conversion between them is always free
  • Confusing capacity with length on a String

Best Answer (HR Friendly)

A String is text your program owns and can change, like your own editable notebook, while &str is just a borrowed peek at some text you cannot alter. Rust functions usually accept the borrowed &str form so they work with any kind of text without copying it.

Code Example

Owned String vs borrowed &str
fn greet(name: &str) {
    println!("Hello, {name}!");
}

fn main() {
    let literal: &str = "Ada";        // &'static str
    let mut owned: String = String::from("Grace");
    owned.push_str(" Hopper");         // mutate the owned buffer

    greet(literal);                    // pass a &str
    greet(&owned);                     // &String coerces to &str

    let slice: &str = &owned[0..5];    // borrow part of the String
    println!("{slice}");
}

Follow-up Questions

  • Why do string literals have a 'static lifetime?
  • How does deref coercion turn &String into &str?
  • When would you accept String by value instead of &str?
  • What does slicing a String on a non-char boundary do?
  • How is a &str represented in memory?

MCQ Practice

1. Which statement about &str is correct?

&str is a fat pointer (pointer + length) borrowing UTF-8 bytes it does not own; it is immutable and can point into a String, a literal, or any buffer.

2. What is the idiomatic parameter type for a function that only reads text?

Accepting &str lets callers pass literals, slices, and owned Strings (via deref coercion) without forcing an allocation.

3. How do you get an owned String from a &str?

Both .to_owned() and .to_string() allocate a new heap buffer and copy the bytes to produce an owned String.

Flash Cards

What does String own?A growable heap-allocated UTF-8 buffer with a pointer, length, and capacity; it frees the buffer when dropped.

What is a &str?An immutable borrowed slice of UTF-8 text: a fat pointer (pointer + length) into a buffer owned elsewhere.

Why take &str, not &String?&str accepts literals, slices, and owned Strings via deref coercion, so the API is more flexible.

Type of a string literal?&'static str — it lives in the binary for the whole program's lifetime.

How to make a &str owned?Call .to_string() or .to_owned() to allocate and copy into a new String.

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