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What is the LEGB Rule (Scope) in Python?

Understand Python's LEGB rule for scope: how Local, Enclosing, Global and Built-in namespaces resolve names, plus global vs nonlocal with clear examples.

mediumQ13 of 61 in Python Est. time: 6 minsLast updated:
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Expected Interview Answer

The LEGB rule describes the order Python searches namespaces to resolve a name: Local, then Enclosing, then Global, then Built-in. The first scope where the name is found wins.

When you reference a variable, Python looks first in the current function's Local scope, then in any Enclosing function scopes, then the module-level Global scope, and finally the Built-in namespace. Assignment inside a function creates a Local name by default, which is why you need the global or nonlocal keyword to rebind names in outer scopes. This lookup chain determines which value a name maps to at runtime.

  • Explains predictable name resolution
  • Prevents accidental variable shadowing bugs
  • Clarifies when to use global and nonlocal
  • Underpins how closures capture variables
  • Makes debugging NameError and UnboundLocalError easier

AI Mentor Explanation

Finding who takes the next catch follows a chain of authority: first the fielder right there (Local), then the on-field captain (Enclosing), then the team's head coach (Global), and finally the ICC rulebook (Built-in). Python resolves a name the same way, stopping at the first level that answers.

Step-by-Step Explanation

  1. Step 1

    Check Local

    Python first looks for the name in the current function or comprehension's own namespace.

  2. Step 2

    Check Enclosing

    If not found locally, it searches any enclosing function scopes from innermost outward (relevant to closures).

  3. Step 3

    Check Global

    Next it looks at the module-level namespace where top-level names and imports live.

  4. Step 4

    Check Built-in

    Finally it searches the built-in namespace containing names like len, print, and range.

  5. Step 5

    Rebind with keywords

    Use global to assign to a module-level name or nonlocal to assign to an enclosing scope name from inside a function.

What Interviewer Expects

  • Correct expansion of L, E, G, B in order
  • Understanding that assignment defaults to Local scope
  • Knowing when global vs nonlocal is needed
  • Connecting enclosing scope to closures
  • Explaining UnboundLocalError with an example

Common Mistakes

  • Reversing the order (searching Global before Local)
  • Thinking a bare assignment updates a global variable
  • Confusing nonlocal with global
  • Believing loops or if-blocks create new scopes
  • Forgetting that comprehensions have their own local scope in Python 3

Best Answer (HR Friendly)

LEGB is just the order Python uses to figure out what a variable name refers to: it checks the local function first, then any function around it, then the whole file, and finally Python's built-in names. It uses the first match it finds.

Code Example

LEGB resolution and nonlocal
x = "global"            # Global

def outer():
    x = "enclosing"      # Enclosing
    def inner():
        x = "local"      # Local
        print(x)         # -> local
    inner()
    print(x)             # -> enclosing

outer()
print(x)                 # -> global
print(len)               # -> Built-in name still visible

def counter():
    count = 0
    def bump():
        nonlocal count   # rebind the enclosing 'count'
        count += 1
        return count
    return bump

c = counter()
print(c(), c())          # -> 1 2

Follow-up Questions

  • What is the difference between global and nonlocal?
  • Why does assigning to a variable inside a function cause UnboundLocalError?
  • How does the LEGB rule relate to closures?
  • Do list comprehensions create their own scope in Python 3?
  • What names live in the built-in namespace and how can you inspect them?

MCQ Practice

1. What does LEGB stand for in the correct search order?

Python searches Local first, then Enclosing, then Global, then Built-in, stopping at the first match.

2. Which keyword lets an inner function rebind a variable defined in an enclosing (but not global) function?

nonlocal binds to the nearest enclosing function scope; global binds to the module-level namespace.

3. By default, assigning to a name inside a function creates a name in which scope?

Assignment inside a function creates a local name unless global or nonlocal is declared.

Flash Cards

What does LEGB stand for?Local, Enclosing, Global, Built-in — the order Python searches namespaces for a name.

What scope does a bare assignment in a function use?Local — unless you declare the name global or nonlocal.

global vs nonlocal?global rebinds a module-level name; nonlocal rebinds the nearest enclosing function's name.

Which scope holds len and print?The Built-in namespace, searched last in the LEGB chain.

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